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關(guan)于單片機(ji)復位的相關(guan)問題詳解 時間:2018-07-26      來源:未(wei)知

關于單片機復位的相關問題詳(xiang)解(jie)

單片(pian)機(ji)的(de)(de)復(fu)(fu)位(wei)電路就(jiu)像計(ji)算機(ji)的(de)(de)重新啟動(dong)部(bu)分(fen)。當(dang)計(ji)算機(ji)死機(ji)時,從開始(shi)執(zhi)(zhi)行(xing)復(fu)(fu)位(wei)按鈕內(nei)部(bu)的(de)(de)程(cheng)(cheng)序。單片(pian)機(ji)是一樣的(de)(de)。當(dang)MCU系統運行(xing)時,程(cheng)(cheng)序受到(dao)環境干擾(rao)的(de)(de)干擾(rao)而運行(xing)。復(fu)(fu)位(wei)按鈕內(nei)部(bu)的(de)(de)程(cheng)(cheng)序從一開始(shi)就(jiu)自動(dong)執(zhi)(zhi)行(xing)。

相關解答一:請問單片機復(fu)位到底是(shi)什么(me)意思(si)

單(dan)(dan)(dan)片機復(fu)位(wei)就是(shi)讓單(dan)(dan)(dan)片機所有必要寄存器(qi)(qi)(個(ge)別(bie)寄存器(qi)(qi)復(fu)位(wei)狀態不(bu)(bu)(bu)確定(ding)或某(mou)些(xie)位(wei)不(bu)(bu)(bu)確定(ding)但肯(ken)定(ding)不(bu)(bu)(bu)影響正(zheng)(zheng)常工作)、外設恢復(fu)到原(yuan)始狀態,程(cheng)序(xu)從啟動地址開始執行。屏(ping)(ping)(ping)的(de)資(zi)料上(shang)說大多因(yin)為復(fu)位(wei)不(bu)(bu)(bu)正(zheng)(zheng)確,那就有可能是(shi)真(zhen)的(de),引起的(de)原(yuan)因(yin)有二,一是(shi)硬件復(fu)位(wei)脈沖(chong)電(dian)平不(bu)(bu)(bu)正(zheng)(zheng)確或者(zhe)寬(kuan)度(du)不(bu)(bu)(bu)夠,二是(shi)復(fu)位(wei)尚未完成單(dan)(dan)(dan)片機就操(cao)作液晶屏(ping)(ping)(ping)了。解決辦法也是(shi)兩個(ge):一、使用單(dan)(dan)(dan)片機IO口給屏(ping)(ping)(ping)提供復(fu)位(wei)信(xin)號,并保證復(fu)位(wei)脈沖(chong)寬(kuan)度(du)。二、開機啟動后(hou),經過足夠延時(shi)時(shi)間(手冊上(shang)會有)后(hou)再對屏(ping)(ping)(ping)進行操(cao)作。

相關解答(da)二:單(dan)片機(ji)復位是什么概念

也就是(shi)從頭再(zai)來的意思(si),就像你把(ba)電腦重啟一(yi)樣

相關(guan)解答三:在單片機電路(lu)中(zhong),為什么需要復位電路(lu)

復(fu)(fu)(fu)位的(de)主要作用是(shi)把(ba)(ba)單(dan)(dan)(dan)片(pian)(pian)(pian)(pian)機(ji)(ji)內部的(de)特殊功能(neng)寄存器置于初始狀態(tai),使(shi)單(dan)(dan)(dan)片(pian)(pian)(pian)(pian)機(ji)(ji)硬件、軟(ruan)件從一(yi)個確定(ding)的(de)、唯一(yi)的(de)起(qi)點開(kai)始工(gong)作。開(kai)機(ji)(ji)時(shi)(shi)稱為上電(dian)復(fu)(fu)(fu)位,工(gong)作中異(yi)常時(shi)(shi)可以手(shou)動(dong)復(fu)(fu)(fu)位,完善的(de)設(she)計(ji)是(shi)“看(kan)門狗”復(fu)(fu)(fu)位。看(kan)門狗電(dian)路是(shi)獨立的(de)模塊,內部有不間斷工(gong)作的(de)計(ji)時(shi)(shi)器,單(dan)(dan)(dan)片(pian)(pian)(pian)(pian)機(ji)(ji)要在設(she)定(ding)的(de)時(shi)(shi)間內把(ba)(ba)計(ji)時(shi)(shi)器清零,使(shi)計(ji)時(shi)(shi)器重新開(kai)始計(ji)時(shi)(shi),否則(ze),計(ji)時(shi)(shi)器溢(yi)出(chu)時(shi)(shi)就復(fu)(fu)(fu)位單(dan)(dan)(dan)片(pian)(pian)(pian)(pian)機(ji)(ji)。即單(dan)(dan)(dan)片(pian)(pian)(pian)(pian)機(ji)(ji)沒有定(ding)時(shi)(shi)來(lai)“簽到”,說(shuo)明單(dan)(dan)(dan)片(pian)(pian)(pian)(pian)機(ji)(ji)有故障,看(kan)門狗就輸出(chu)復(fu)(fu)(fu)位信號,使(shi)單(dan)(dan)(dan)片(pian)(pian)(pian)(pian)機(ji)(ji)進(jin)入初始化狀態(tai)。

相(xiang)關解答四(si):有誰知道(dao)單片機的復位條(tiao)件及概念

復位(wei)(wei)(wei)(wei)(wei)的(de)主(zhu)要作用(yong)是把特殊功能(neng)(neng)(neng)寄存器的(de)數據刷新為默認數據,單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji)在(zai)(zai)運(yun)(yun)算(suan)過程(cheng)中(zhong)由(you)于干擾(rao)等外界原因(yin)造成寄存器中(zhong)數據混亂不(bu)(bu)能(neng)(neng)(neng)使(shi)其(qi)正(zheng)(zheng)常繼續執行(xing)程(cheng)序(xu)(xu)(稱死機(ji)(ji)(ji)(ji))或產生(sheng)的(de)結(jie)果(guo)(guo)不(bu)(bu)正(zheng)(zheng)確時(shi)均(jun)需(xu)要復位(wei)(wei)(wei)(wei)(wei),以使(shi)程(cheng)序(xu)(xu)重新開始運(yun)(yun)行(xing)。現在(zai)(zai)好多(duo)單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji)內部集成有上(shang)(shang)(shang)電(dian)(dian)(dian)(dian)(dian)復位(wei)(wei)(wei)(wei)(wei)電(dian)(dian)(dian)(dian)(dian)路(lu),這種(zhong)單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji)不(bu)(bu)需(xu)要外接(jie)(jie)上(shang)(shang)(shang)電(dian)(dian)(dian)(dian)(dian)復位(wei)(wei)(wei)(wei)(wei)電(dian)(dian)(dian)(dian)(dian)路(lu)。如(ru)果(guo)(guo)是普通(tong)(tong)不(bu)(bu)帶內部上(shang)(shang)(shang)電(dian)(dian)(dian)(dian)(dian)復位(wei)(wei)(wei)(wei)(wei)電(dian)(dian)(dian)(dian)(dian)路(lu)的(de)單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji),沒有上(shang)(shang)(shang)電(dian)(dian)(dian)(dian)(dian)復位(wei)(wei)(wei)(wei)(wei)電(dian)(dian)(dian)(dian)(dian)路(lu),一(yi)般不(bu)(bu)會正(zheng)(zheng)常工作!單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji)復位(wei)(wei)(wei)(wei)(wei)電(dian)(dian)(dian)(dian)(dian)路(lu)相對比較(jiao)簡單(dan)(dan)(dan),一(yi)般來說運(yun)(yun)用(yong)最多(duo)的(de)就(jiu)是上(shang)(shang)(shang)電(dian)(dian)(dian)(dian)(dian)復位(wei)(wei)(wei)(wei)(wei)。所謂上(shang)(shang)(shang)電(dian)(dian)(dian)(dian)(dian)復位(wei)(wei)(wei)(wei)(wei)是指在(zai)(zai)單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji)通(tong)(tong)電(dian)(dian)(dian)(dian)(dian)的(de)瞬間(jian),因(yin)各部分電(dian)(dian)(dian)(dian)(dian)路(lu)電(dian)(dian)(dian)(dian)(dian)壓(ya)未正(zheng)(zheng)常建立(li),這時(shi)單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji)會出(chu)現運(yun)(yun)行(xing)錯誤,因(yin)此在(zai)(zai)上(shang)(shang)(shang)電(dian)(dian)(dian)(dian)(dian)時(shi)應使(shi)單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji)復位(wei)(wei)(wei)(wei)(wei),復位(wei)(wei)(wei)(wei)(wei)時(shi)間(jian)要求大于上(shang)(shang)(shang)電(dian)(dian)(dian)(dian)(dian)時(shi)間(jian)。以單(dan)(dan)(dan)片(pian)(pian)(pian)機(ji)(ji)(ji)(ji)AT89C51為例,其(qi)復位(wei)(wei)(wei)(wei)(wei)電(dian)(dian)(dian)(dian)(dian)路(lu)如(ru)下圖所示,在(zai)(zai)RST端(duan)上(shang)(shang)(shang)接(jie)(jie)一(yi)個(ge)電(dian)(dian)(dian)(dian)(dian)容(rong)至VCC端(duan),下接(jie)(jie)一(yi)個(ge)電(dian)(dian)(dian)(dian)(dian)阻至地。當(dang)VCC端(duan)通(tong)(tong)電(dian)(dian)(dian)(dian)(dian)時(shi),復位(wei)(wei)(wei)(wei)(wei)電(dian)(dian)(dian)(dian)(dian)路(lu)通(tong)(tong)過電(dian)(dian)(dian)(dian)(dian)容(rong)給RST端(duan)加一(yi)個(ge)高(gao)電(dian)(dian)(dian)(dian)(dian)平,此高(gao)電(dian)(dian)(dian)(dian)(dian)平信號隨VCC對電(dian)(dian)(dian)(dian)(dian)容(rong)的(de)充電(dian)(dian)(dian)(dian)(dian)而(er)逐漸降低,因(yin)此要保(bao)證(zheng)電(dian)(dian)(dian)(dian)(dian)容(rong)的(de)充電(dian)(dian)(dian)(dian)(dian)時(shi)間(jian)足夠長來完成復位(wei)(wei)(wei)(wei)(wei)功能(neng)(neng)(neng)。

相(xiang)關解答五:51單(dan)片機如何(he)實現“復位(wei)”

首(shou)先需要(yao)明確,程(cheng)(cheng)序重(zhong)頭開始(shi)執(zhi)行(xing)(xing)(xing)是(shi)(shi)指某一段程(cheng)(cheng)序(或者一個(ge)函數)重(zhong)新開始(shi)執(zhi)行(xing)(xing)(xing),還是(shi)(shi)你(ni)所(suo)(suo)謂的“復(fu)(fu)(fu)位(wei)”讓(rang)單片機(ji)重(zhong)啟(qi)?如(ru)果不(bu)是(shi)(shi)特殊需求(qiu),建議不(bu)要(yao)讓(rang)單片機(ji)復(fu)(fu)(fu)位(wei)以使程(cheng)(cheng)序重(zhong)新運行(xing)(xing)(xing)。從你(ni)描述看,你(ni)所(suo)(suo)執(zhi)行(xing)(xing)(xing)的程(cheng)(cheng)序肯(ken)定(ding)是(shi)(shi)長時間(jian)占有CPU導致不(bu)能(neng)實時監測紅外(wai)信(xin)號,很(hen)明顯(xian)不(bu)能(neng)用(yong)查詢(xun)方式,改用(yong)中(zhong)斷即可,至于(yu)中(zhong)斷后如(ru)何停止原來運行(xing)(xing)(xing)的程(cheng)(cheng)序再重(zhong)新開始(shi)運行(xing)(xing)(xing)就是(shi)(shi)你(ni)的事了。那么(me)我浮求(qiu)就是(shi)(shi)要(yao)檢測到紅外(wai)信(xin)號后“復(fu)(fu)(fu)位(wei)”單片機(ji)怎么(me)辦呢?直接(jie)將紅外(wai)信(xin)號接(jie)到復(fu)(fu)(fu)位(wei)引(yin)腳上(假設你(ni)單片機(ji)是(shi)(shi)高電平復(fu)(fu)(fu)位(wei)),若(ruo)是(shi)(shi)低(di)電平復(fu)(fu)(fu)位(wei),則(ze)取反。不(bu)過要(yao)注意:1、復(fu)(fu)(fu)位(wei)信(xin)號要(yao)持續一定(ding)時間(jian)才(cai)能(neng)復(fu)(fu)(fu)位(wei);2、自然(ran)界中(zhong)紅外(wai)干擾(rao)很(hen)多,很(hen)有可能(neng)你(ni)單片機(ji)運行(xing)(xing)(xing)著運行(xing)(xing)(xing)著就復(fu)(fu)(fu)位(wei)了~~3、若(ruo)紅外(wai)接(jie)收器還肩負其他如(ru)信(xin)號傳輸(shu)任務(wu),很(hen)明顯(xian)這樣(yang)不(bu)行(xing)(xing)(xing)!

相(xiang)關解答六(liu):單(dan)片機復位操作有(you)什(shen)么和什(shen)么兩總方式

單(dan)片機復(fu)(fu)位(wei)(wei)操作基本有手動復(fu)(fu)位(wei)(wei)、看門狗復(fu)(fu)位(wei)(wei)、電源電壓(ya)異(yi)常復(fu)(fu)位(wei)(wei)、時(shi)鐘失步(bu)復(fu)(fu)位(wei)(wei)。方(fang)式主(zhu)要有高電平(ping)復(fu)(fu)位(wei)(wei)、低電平(ping)復(fu)(fu)位(wei)(wei)兩種。

相(xiang)關解答七:51單片機開機為什么要復位

電腦要(yao)開機關機,手機要(yao)重(zhong)啟(qi),單(dan)片機也是計(ji)算機系統,也要(yao)復(fu)位(wei)進行重(zhong)啟(qi),有(you)的復(fu)位(wei)是外部復(fu)位(wei)一(yi)般是人為的復(fu)位(wei)操作,還有(you)就是看門口(kou)復(fu)位(wei),這是出(chu)現在系統出(chu)錯的情況下發(fa)生的復(fu)位(wei)。

相關解答八:單片(pian)機復位電路(lu)問(wen)題

我認為(wei)(wei) 絳(jiang)紅的(de)(de)(de)藍 同學 說(shuo)(shuo)的(de)(de)(de)不太好。電(dian)(dian)(dian)容確實可(ke)以起到(dao)按(an)(an)鍵(jian)去除抖動的(de)(de)(de)作用(yong)(yong),但(dan)是(shi)(shi)(shi)(shi)這(zhe)里(li)的(de)(de)(de)電(dian)(dian)(dian)容還(huan)有一(yi)個更重要的(de)(de)(de)作用(yong)(yong)就(jiu)是(shi)(shi)(shi)(shi)上(shang)(shang)(shang)(shang)電(dian)(dian)(dian)復(fu)位(wei)(wei),因為(wei)(wei)考慮到(dao)芯片剛(gang)(gang)剛(gang)(gang)上(shang)(shang)(shang)(shang)電(dian)(dian)(dian)時(shi)(shi)由于(yu)供電(dian)(dian)(dian)不穩定而做出錯誤(wu)的(de)(de)(de)計算,所(suo)以增加(jia)一(yi)個上(shang)(shang)(shang)(shang)電(dian)(dian)(dian)復(fu)位(wei)(wei)以達到(dao)延時(shi)(shi)啟動CPU的(de)(de)(de)目的(de)(de)(de),使(shi)(shi)芯片能(neng)夠正(zheng)常工作。雖然(ran)現(xian)在很多芯片自帶了(le)上(shang)(shang)(shang)(shang)電(dian)(dian)(dian)延時(shi)(shi)功能(neng),但(dan)是(shi)(shi)(shi)(shi)我們一(yi)般還(huan)是(shi)(shi)(shi)(shi)會(hui)增加(jia)額外的(de)(de)(de)上(shang)(shang)(shang)(shang)電(dian)(dian)(dian)復(fu)位(wei)(wei)電(dian)(dian)(dian)路,提高可(ke)靠性。上(shang)(shang)(shang)(shang)電(dian)(dian)(dian)復(fu)位(wei)(wei)是(shi)(shi)(shi)(shi)如此工作的(de)(de)(de),此時(shi)(shi)不用(yong)(yong)考慮按(an)(an)鍵(jian)和你圖中1K電(dian)(dian)(dian)阻的(de)(de)(de)作用(yong)(yong)。上(shang)(shang)(shang)(shang)電(dian)(dian)(dian)瞬間(jian)(jian),電(dian)(dian)(dian)壓VCC短時(shi)(shi)間(jian)(jian)內從(cong)0V上(shang)(shang)(shang)(shang)升到(dao)5V(比方說(shuo)(shuo)5V),這(zhe)一(yi)瞬間(jian)(jian)相當于(yu)交流(liu)電(dian)(dian)(dian),電(dian)(dian)(dian)容相當于(yu)導線,5V的(de)(de)(de)電(dian)(dian)(dian)壓全部加(jia)在10K電(dian)(dian)(dian)阻上(shang)(shang)(shang)(shang),也就(jiu)是(shi)(shi)(shi)(shi)說(shuo)(shuo),這(zhe)時(shi)(shi)RST的(de)(de)(de)電(dian)(dian)(dian)平(ping)狀態為(wei)(wei)高電(dian)(dian)(dian)平(ping)。但(dan)是(shi)(shi)(shi)(shi)從(cong)上(shang)(shang)(shang)(shang)電(dian)(dian)(dian)開(kai)始,電(dian)(dian)(dian)容自己就(jiu)慢慢充電(dian)(dian)(dian),其兩(liang)端(duan)(duan)電(dian)(dian)(dian)壓呈曲線上(shang)(shang)(shang)(shang)升,最(zui)終達到(dao)5V,也就(jiu)是(shi)(shi)(shi)(shi)說(shuo)(shuo)其正(zheng)端(duan)(duan)電(dian)(dian)(dian)位(wei)(wei)為(wei)(wei)5V,負端(duan)(duan)電(dian)(dian)(dian)位(wei)(wei)為(wei)(wei)0V,其負端(duan)(duan)也就(jiu)正(zheng)好是(shi)(shi)(shi)(shi)RST,此時(shi)(shi)RST為(wei)(wei)低(di)電(dian)(dian)(dian)平(ping),單片機開(kai)始正(zheng)常工作。添加(jia)按(an)(an)鍵(jian)是(shi)(shi)(shi)(shi)為(wei)(wei)了(le)手(shou)動復(fu)位(wei)(wei),一(yi)般那個1K電(dian)(dian)(dian)阻可(ke)以不加(jia)。當按(an)(an)鍵(jian)按(an)(an)下時(shi)(shi),電(dian)(dian)(dian)容兩(liang)端(duan)(duan)構成(cheng)回(hui)路并放電(dian)(dian)(dian),使(shi)(shi)RST端(duan)(duan)重新變(bian)為(wei)(wei)高電(dian)(dian)(dian)平(ping),按(an)(an)鍵(jian)抬起時(shi)(shi)電(dian)(dian)(dian)容又(you)充電(dian)(dian)(dian)使(shi)(shi)RST變(bian)回(hui)低(di)電(dian)(dian)(dian)平(ping)。

相關解答九:單(dan)片機復位是怎么回事

初(chu)始(shi)(shi)化的(de)問題在上(shang)電(dian)復位(wei)的(de)時(shi)(shi)候 寄存(cun)器(qi)被(bei)初(chu)始(shi)(shi)化但是在按(an)鍵復位(wei)的(de)時(shi)(shi)候 有一部分(fen)寄存(cun)器(qi)初(chu)始(shi)(shi)化,還有一些(xie)沒有被(bei)初(chu)始(shi)(shi)化,如IO等 這些(xie)是根據你當時(shi)(shi)的(de)運行情況(kuang)來的(de) 所(suo)以 在做單片機設(she)計的(de)時(shi)(shi)候,最好了解一下(xia)所(suo)有寄存(cun)器(qi) 在各種不同復位(wei)狀態(tai)下(xia)的(de) 狀態(tai) 然后軟件初(chu)始(shi)(shi)化 就不會發生上(shang)面(mian)的(de)問題了

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